Problem 5: Suggest one beam design problem that you would consider relevant and useful for Power Engineers. Use any timber sizes and material grades from textbook Appendix E or others of your own design. Design only the deck boards and the side beams. The walkway has to be 3.5 ft wide and be able to support a uniformly distributed load of 60 lb/ft 2 over its entire surface. Rigid supports are available on each side of the pipeline, 14 ft apart. Problem 4: Design a walkway to span a newly installed pipeline in your plant. Compute the the maximum allowable uniformly distributed load it could carry while limiting the stress due to bending to one-fifth of the ultimate strength. Problem 3: The figure shows the cross-section of a beam built from aluminum 6061-T6. Assuming that the load acts at the center of the beam, calculate the required section modulus of the beam to limit the bending stress to 140 MPa then select the lightest SI W-beam that satisfies the criteria. Each beam carries the weight of 20 m Sch 40 DN-600 pipe (see PanGlobal Academic Extract), filled with oil of 0.9 SG. Problem 2: A pipeline is simply supported above ground on horizontal beams, 4.5 m long. Does this construction meet the design requirements? AISC recommends that the maximum bending stress for building-like structures under static loads be kept below 0.66×S y. Formula Method: Statically Indeterminate Beams For Problems 916 through 929. The beam is constructed using W200×100 I-beam profile from AISI-1020 cold rolled material. bending and horizontal shear, and compare them with the allowable stresses. Problem 1: A simply supported beam, 9.9 meters long, is loaded with concentrated loads as follows: Note: if not specified, use σ design = 0.6×σ YS, where σ YS is the Yield Strength, from textbook Appendix B. no twisting, buckling or crippling occurs.if the material has different strengths in tension and compression (example cast iron or other anisotropic materials) then separate calculations are required for both tension and compression surfaces.the beam material is homogeneous and has equal strength in tension and compression.the resulting stress is below the limit of proportionality of the material.all the loads act perpendicular to the longitudinal axis of the beam.the beam is straight, relatively long and narrow and of uniform cross-section.The flexure formula is valid if the following criteria are met: Z x is called section modulus and is a term that combines the moment of inertia and the distance to the extreme fiber ( Z x = I x / c).c is the maximum distance from the centroidal axis to the extreme fiber (again, this can be to the top or bottom of the shape).I x is the moment of inertia about x (horizontal) centroidal axis.if the maximum bending stress is required then M is the maximum bending moment acting on the beam.M is the bending moment along the length of the beam where the stress is calculated. σ max is the maximum stress at the farthest surface from the neutral axis (it can be top or bottom).To determine the maximum stress due to bending the flexure formula is used:
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